Maths
Given the parabola of equation y = x² + 6x, indicated by V the vertex, determines the area of the triangle AVB, where A and B are the points of intersection of the parabola with the straight line of equation y = 5.
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Please help this student
[V=(-3,-9), A=(-3-√14, 5), B=(-3+√14, 5).]
[AB=9, AV=BV=√210, h=5-(-9)= 14]
Area of AVB: [(base. hight)/2]
Base is AB= 9, hight=14 so: Area of AVB is 63.
